n=n(n-5)(n-9)-n^2(n-13)

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Solution for n=n(n-5)(n-9)-n^2(n-13) equation: 



n=n(n-5)(n-9)-n^2(n-13)

We move all terms to the left:

n-(n(n-5)(n-9)-n^2(n-13))=0

We multiply parentheses ..

-(n(+n^2-9n-5n+45)-n^2(n-13))+n=0



We calculate terms in parentheses: -(n(+n^2-9n-5n+45)-n^2(n-13)), so:

n(+n^2-9n-5n+45)-n^2(n-13)

We multiply parentheses

n^3-9n^2-5n^2-n^2(n-13)+45n

We do not support enpression: n^3

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